Answer:
Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : (9*3)*6-(6*(9*3))=0 STEP 1 : Equations which are always true 1.1 Solve 0 = 0. This equation is a tautology (Something which is always true) Equation is alway true
Hoped I helped
Answer:
y > x + 1 ; y ≤ 10 ; x ≥ 0
Step-by-step explanation:
First, we need to get the equation of the straight line. The equation of the straight line is expressed as y = mx+c
m is the slope
c is the y-intercept
Using the coordinate points (0, 1) and (1,2)
m = (2-1)/(1-0)
m = 1/1 = 1
y-intercept c = 1 (the point where the line cuts the y-axis)
Substitute;
Since y = mx+c, then y = 1x + 1
y = x+1
Since the line is a broken line and shaded above, then y > x+1
Also, the point shaded on the graph indicates y ≤ 10 ; x ≥ 0
1/2 because there are 3 odd numbers on a number cube and 6 numbers in total and 3/6 simplified is 1/2
The distance between two points on the plane is given by the formula below
![\begin{gathered} A=(x_1,y_1),B=(x_2,y_2) \\ \Rightarrow d(A,B)=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%28x_1%2Cy_1%29%2CB%3D%28x_2%2Cy_2%29%20%5C%5C%20%5CRightarrow%20d%28A%2CB%29%3D%5Csqrt%5B%5D%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D%20%5Cend%7Bgathered%7D)
Therefore, in our case,
Thus,
![\begin{gathered} \Rightarrow d(A,B)=\sqrt[]{(-1-5)^2+(-3-2)^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61} \\ \Rightarrow d(A,B)=\sqrt[]{61} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5CRightarrow%20d%28A%2CB%29%3D%5Csqrt%5B%5D%7B%28-1-5%29%5E2%2B%28-3-2%29%5E2%7D%3D%5Csqrt%5B%5D%7B6%5E2%2B5%5E2%7D%3D%5Csqrt%5B%5D%7B36%2B25%7D%3D%5Csqrt%5B%5D%7B61%7D%20%5C%5C%20%5CRightarrow%20d%28A%2CB%29%3D%5Csqrt%5B%5D%7B61%7D%20%5Cend%7Bgathered%7D)
Therefore, the answer is sqrt(61)
In general,
Remember that
Therefore,
Answer:
Step-by-step explanation:
Substitute x=3 and y=-6 in the expression.
Evaluate.
