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Readme [11.4K]
4 years ago
7

-1/6(x-24)<4 Please answer!!!

Mathematics
1 answer:
Verdich [7]4 years ago
8 0

-1/6(x-24) < 4

x-24 > -6*4 ... note the inequality sign flips, see "extra info" below

x-24 > -24

x-24+24 > -24+24 ... add 24 to both sides

x > 0

Therefore, the answer is x > 0 meaning that x is greater than 0.

To graph this, draw a number line. Plot an open circle at 0. Then shade to the right. The open circle or hole says to the reader "do not include this value as part of the solution set"

extra info: the inequality sign flips only when you multiply both sides by a negative number. In this case, we multiplied both sides by -6.

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In an experiment on the behavior of young children, each placed in an area with five toys. The variable of interest X is the num
Fofino [41]

Answer:

a)15 b)2.34 c)by taking sum of number of toy divide to its numberings

Step-by-step explanation:

  • in roman a number of toys is equal to the sum of all toys and standard deviation is obtained from formula
4 0
3 years ago
Estimate the answer to 65.78 + 13.43 by first rounding each number to the nearest tenth.
gizmo_the_mogwai [7]
65.8 + 13.4 =  79 .2. So the answer is c 
6 0
3 years ago
For <img src="https://tex.z-dn.net/?f=e%5E%7B-x%5E2%2F2%7D" id="TexFormula1" title="e^{-x^2/2}" alt="e^{-x^2/2}" align="absmiddl
nevsk [136]
I'm assuming you're talking about the indefinite integral

\displaystyle\int e^{-x^2/2}\,\mathrm dx

and that your question is whether the substitution u=\dfrac x{\sqrt2} would work. Well, let's check it out:

u=\dfrac x{\sqrt2}\implies\mathrm du=\dfrac{\mathrm dx}{\sqrt2}
\implies\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt2\int e^{-(\sqrt2\,u)^2/2}\,\mathrm du
=\displaystyle\sqrt2\int e^{-u^2}\,\mathrm du

which essentially brings us to back to where we started. (The substitution only served to remove the scale factor in the exponent.)

What if we tried u=\sqrt t next? Then \mathrm du=\dfrac{\mathrm dt}{2\sqrt t}, giving

=\displaystyle\frac1{\sqrt2}\int \frac{e^{-(\sqrt t)^2}}{\sqrt t}\,\mathrm dt=\frac1{\sqrt2}\int\frac{e^{-t}}{\sqrt t}\,\mathrm dt

Next you may be tempted to try to integrate this by parts, but that will get you nowhere.

So how to deal with this integral? The answer lies in what's called the "error function" defined as

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, taking the derivative of both sides yields

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

and so the antiderivative would be

\displaystyle\int e^{-x^2/2}\,\mathrm dx=\sqrt{\frac\pi2}\mathrm{erf}\left(\frac x{\sqrt2}\right)

The takeaway here is that a new function (i.e. not some combination of simpler functions like regular exponential, logarithmic, periodic, or polynomial functions) is needed to capture the antiderivative.
3 0
3 years ago
Please help! I'm not sure on what I do.​
Alisiya [41]

Answer:

slope= 6.25

Step-by-step explanation:

the slope represents the meters he travels per second

5 0
3 years ago
Read 2 more answers
A jacket costs $35 and has an 8 percent tax rate. Which expression will find the cost of the tax on the jacket?
Neporo4naja [7]

Answer:

35x.08

Step-by-step explanation:

35x.08 equals 2.8 which means there is a tax of $2.08 so your total would be $37.08

7 0
4 years ago
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