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mixer [17]
4 years ago
8

Explain the steps in finding the midpoint of the points (-1,2) and (3,-6). The state the midpoint

Mathematics
1 answer:
blondinia [14]4 years ago
8 0

Answer:

(1, -2)

Step-by-step explanation:

midpoint x = (x₁ + x₂) / 2

midpoint y = (y₁ + y₂) / 2

(\frac{-1 + 3}{2} , \frac{2 + -(6)}{2} )

  = (1, -2)

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3 years ago
Why do the functions f(x) = sin−1(x) and g(x) = cos−1(x) have different ranges?
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We Know that
For a function to have an inverse function, it must be one-to-one—that is, it must pass the Horizontal Line Test.

1. On the interval [–pi/2, pi/2], the function y = sin x is increasing
2. On the interval [–pi/2, pi/2], y = sin x takes on its full range of values, [–1, 1]
3. On the interval [–pi/2, pi/2], y = sin x is one-to-one
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On the restricted domain [–pi/2, pi/2]  y = sin x has a unique inverse function called the inverse sine function. <span>f(x) = sin−1(x)
</span>the range of y=sin x  in the domain [–pi/2, pi/2]  is [-1,1] 
the range of y=sin-1  x  in the domain [-1,1]  is [–pi/2, pi/2]  

1. On the interval [0, pi], the function y = cos x is decreasing
2. On the interval [0, pi], y = cos x takes on its full range of values, [–1, 1]
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cos x has an inverse function on this interval [0, pi]

On the restricted domain [0, pi]  y = cos x has a unique inverse function called the inverse sine function. f(x) = cos−1(x)
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the range of y=cos-1  x  in the domain [-1,1]  is [0, pi] 

the answer is

<span>the values ​​of the range are different because the domain in which the inverse function exists are different</span>  
8 0
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