a = 30
a = 16
-a² + 46a -480 = 0
(-a + 30) (a -16) = 0
(-a)(a) + (-a)(-16) + 30(a) + 30(-16) = 0
-a² + 16a + 30a -480 = 0
-a² + 46a - 480 = 0
(-a + 30) = 0 ; (a - 16) = 0
-a = -30 ; a = 16
a = 30
To check:
a = 30
-(30)² + 46(30) - 480 = 0
-900 + 1380 - 480 = 0
480 - 480 = 0
0 = 0
a = 16
-(16)² + 46(16) - 480 = 0
-256 + 736 - 480 = 0
480 - 480 = 0
0 = 0
<h2>
Answer:</h2>
<h2>
Step-by-step explanation:</h2>
The question in this problem is:
<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>
<em />
First of all, let's name the first variable 
which is the smaller number. Accordingly, the lager number will be 
given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:
So:
1. The sum of 2 consecutive integers can be written as:
2. Nine times the smaller and 5 times the larger can be written as:
Finally, the whole statement:
The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:
The two numbers are:
Answer:
Is not correct. The product not always will be smaller.
Step-by-step explanation:
A fraction could increase a number if you multiply it.
If the numerator is higher to the denominator, it will increase it.
If the numerator is smaller to the denominator, it will decrease it.
<u>For example,</u>
10 x 4/3
For fraction multiplication, multiply the numerators and then multiply the denominators to get
10×4/1×3=40/3= 13,33
13,33 is higher than 10.
5 x 10/3
For fraction multiplication, multiply the numerators and then multiply the denominators to get
5×10/1×3=50/3
16,66 is higher than 5.
