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Karolina [17]
3 years ago
14

The relationship between ttt and rrr is expressed by the equation 2t+3r+6=02t+3r+6=02, t, plus, 3, r, plus, 6, equals, 0. If rrr

increases by 444, which of the following statements about ttt must be true?
Mathematics
1 answer:
Greeley [361]3 years ago
3 0

Question:

The relationship between t and r is expressed by the equation 2t+3r+6 = 0. If r increases by 4, which of the following statements about t must be true?

Answer:

The value of t is reduced by 6 when the value of r is increased by 4

Step-by-step explanation:

Given

2t + 3r + 6 = 0

Required

What happens when r is increased by 4

2t + 3r + 6 = 0 <em>-------- Equation 1</em>

Subtract 2t from both sides

2t + 3r + 6 - 2t = 0 - 2t

3r + 6 = - 2t --- <em>Equation 2</em>

When r is increased by 4, equation 1 becomes

2T + 3(r+4) + 6 = 0

Note that the increment of r also affects the value of t; hence, the new value of t is represented by T

Open bracket

2T + 3r+12 + 6 = 0

Rearrange

2T + 3r+6 +12 = 0

<em>Substitutr -2t for 3r + 6 [From equation 2]</em>

2T -2t +12 = 0

Make T the subject of formula

2T = 2t - 12

Divide both sides by 2

\frac{2T}{2} = \frac{2t - 12}{2}

T = t - 6

This means that the value of t is reduced by 6 when the value of r is increased by 4

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mrs_skeptik [129]

Answer:

Yes.

Step-by-step explanation:

If the slope between successive points have the same slope then they will form a straight line.

Slope = ( 3.5- -1) / (-2 - -8) = 4.5/6  = 3/4

Slope = (12.5 - 3.5) / (10 - -2) = 9 / 12 = 3/4

Slope = (20-12.5)/(20-10) - 7.5/10 = 3/4 .

So the answer is yes.

4 0
3 years ago
An ordinary fair die is a cube with the numbers one through six on the sides represented by painted that. Imagine that such a di
Solnce55 [7]

Answer:

ok so what i think your trying to ask is if we roll two dice that the sum will be more then 6

Two dice

Assuming that the dice are unbiased or not " loaded".

Each side has the same probability, is 1/6 =0.16667, to turn up when rolled, if the die (D) is unbiased. The probability of a side turning up on D1 when 2 dice ( D1,D2) are rolled, is independent of the side turning up in D2. So this is an independent event.

How many ways can one get a sum total of 6 if D1 &D2 are rolled at the same time?

These are the possibilities

Case 1.

D1 =1 & D2=5

Or

D1= 5 & D2=1

Case 2.

D1 =2 & D2=4

Or

D1= 4 & D2= 2

Case 3. D1=3, D2=3

P3 =0.027778

Let's say, P 1 the probability for case 1 and P2 for case 2. There are no other cases.

The final probability P and is the sum total P = P1 + P2 + P3 the probability law of mutually exclusive events.

P1= 0.02778+ 0.02778 =0.055558

P2= 0.02778+0.02778 =0.055558

Same way,

P3=0.027778, when there is only one way to get the sum 6.

So, P = 0.138894

Based on truncating at the sixth decimal place.

A visual representation with two unbiased dice and the possible cases would also give the same result and is a short cut method. I like to derive from the basics.

Hope This Helps!!!

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3 years ago
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yarga [219]

Definition of a rational number:

A rational number is a number that can be written as fraction of integers.


19/10 is a fraction.

19 and 10 are integers.

19/10 follows exactly the definition of a rational number, so it is rational.

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3 years ago
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Answer:

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Step-by-step explanation:

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X< 5 and (- infinity, 5 )
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