Answers: Using the process of completing the square:
1. Isolate the constant by <u>adding 7 to</u> both sides of the equation:
x^2-6x-7+7=0+7
x^2-6x=7
2. Add <u>9</u> to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced:
x^2-6x+9=7+9
x^2-6x+9=16
3. Write the trinomial x2 – 6x + 9 as squared:
<u>(x-3)^2</u> = 16
4. Use the square root property of equality to get x – 3 = ±<u>4</u> .
sqrt[ (x-3)^2 ] = ± sqrt(16)
x-3 = ±4
5. Isolate the variable to get solutions of –1 and 7.
x-3 = ±4
x-3+3 = ±4+3
x = ±4+3
x1=-4+3→x1=-1
x2=+4+3→x2=7
x - y = 14
given the ratio x : y = 5 : 3
then let x = 5x and y = 3x, hence equation can be expressed as
5x + 3x = 56
8x = 56 ( divide both sides by 8 )
x = 7
Hence x = 5 × 7 = 35 and y = 3 × 7 = 21
Thus x - y = 35 - 21 = 14
Answer:
-0.39 and 3.89
Step-by-step explanation:
By using the quadratic formula it will give you the answers of x= 7 + or - square root of 73 all over 4.
When you do the math of both of the equations it will give you the answers above
The answer to this question is A). 39 b). 56
