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Allushta [10]
3 years ago
14

3. a. Come up with a probability problem that deals with dependent events.

Mathematics
1 answer:
Finger [1]3 years ago
3 0

A girl has 20 marbles

10 are red, 7 are blue, and 3 are green

If she picks 5 marbles, without replacing them, what are the chances all 5 are red?

10/20 * 9/19 * 8/18 *7/17 * 6/16

1/2 * 9/19 * 4/9 * 7/17 * 3/8

1/2 * 1/19 * 3/2

1/76

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For an outdoor concert by the city​ orchestra, concert organizers estimate that 19 comma 000 people will attend if it is not rai
Amiraneli [1.4K]

Answer:

14,800 people are expected to attend the concert

Step-by-step explanation:

In this question, we are tasked with calculating the expected number of people that will attend a concert on a particular day.

The key to answering this question is to multiply the individual probabilities of the two events by the expected number of people

Mathematically, what we obtain is the following;

The expected number of people at the concert = (probability of raining × expected number of people when it rains) + (probability of not raining × Expected number of people when it does not rain)

From the question, we identify that;

Probability of raining = 30% = 30/100 = 0.3

Probability of not raining = 1-probability of raining = 1-0.3 = 0.7

Expected number of people when it rains = 5,000

Expected number of people when there is no rain = 19,000

we plus these vales into the equation we have;

The expected number of people at the concert =( 0.3 × 5,000) + (0.7 × 19,000) = 1,500 + 13,300 = 14,800 people

6 0
4 years ago
Help please i really need it
mihalych1998 [28]

Answer:

3x - 4

Step-by-step explanation:

Slope (m): 3

Y-intercept (c): = -4

Equation of Line: Y=mx + c

                            Y=3x -4

3 0
3 years ago
Question 9:
Arte-miy333 [17]

Answer:

I think the answer is.. .

Step-by-step explanation:

(b)

7 0
3 years ago
You are going to make 5 assemblies, where each assembly requires the use of 1 Type A Bolt. You have a container of bolts that co
OverLord2011 [107]

Answer:

Step-by-step explanation:

You are to make 5 assemblies.

Each assembly requires the use of 1 Type A bolt.

To make the 5 assemblies, you need 5 Type A bolts.

The container of bolts has a total of 60 bolts.

The focus - Type A bolts - is 20 out of this 60.

The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3

(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?

- The exact number of Type A bolts you need for the 5 assemblies is 5

1/3 × 5/10 =  5/30 =  1/6 =  0.167

(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:

1/3 × 4/10 = 0.133

1/3 × 3/10 = 0.1

1/3 × 2/10 = 0.067

1/3 × 1/10 = 0.033

1/3 × 0/10 = 0

TOTAL = 0.333

7 0
3 years ago
I need help plzzzzzzzzzzzzzzzzzzzzz
blagie [28]

Answer:

Step-by-step explanation:

Start box

180 = 89+42+x

180-89-42=x

49 = x

2nd box

180 = 84+58+x

180-84-58=x

38 = x

3rd box

180=74+2x

180-74=2x

106/2 = x

53 = x

4th box

180=102+2x

180-102=2x

78/2 = x

39 = x

4th box

180 = 73+81 +x

180-73-81=x

26 = x

5th box

180=2*54+x

180 - 2*54 = x

72 = x

6th box

180=62-2x

180-62=2x

118=2x

118/2=x

59 = x

7th box

180 = 2*68 + x

180-2*68=x

44 = x

3 0
3 years ago
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