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Natasha_Volkova [10]
2 years ago
10

Given the sequence 128, −32, 8… , which of the following statements is TRUE? *

Mathematics
2 answers:
scoray [572]2 years ago
6 0

Answer:

C

Step-by-step explanation:

The sequence has a common ratio r between consecutive terms

r = \frac{a_{2} }{a_{1} } = \frac{-32}{128} = - \frac{1}{4}

r = \frac{a_{3} }{a_{2} } = \frac{8}{-32} = - \frac{1}{4}

Thus the sequence is geometric with common ratio r = - \frac{1}{4}

Hoochie [10]2 years ago
5 0

Answer:

C

Step-by-step explanation:

Because the ratio between 128 and -32 is the same as the ratio between -32 and 8

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B= 133°  C= 47°

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3 years ago
To rationalize the denominator of 2/square 13+ squared 11 , you should multiply the expression by which fraction?
eimsori [14]

<u><em>Answer:</em></u>

You should multiply the expression by \frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}}

<u><em>Explanation:</em></u>

To rationalize any expression, you must multiply it by its conjugate. A conjugate is defined as a similar expression to the original one but with an opposite sign

<u>This means that:</u>

The conjugate of a + b would be a -  b

Now, the given expression is \frac{2}{\sqrt{13}+\sqrt{11}}

<u>Consider the denominator:</u>

From the above, we can conclude that the conjugate of \sqrt{13}+\sqrt{11} is \sqrt{13}-\sqrt{11}

<u>And, remember that</u> we need to keep the value of the expression unchanged. This means that we must multiply both the numerator and the denominator by the same value

<u>Therefore:</u>

You should multiply the expression by \frac{\sqrt{13}-\sqrt{11}}{\sqrt{13}-\sqrt{11}} in order to rationalize the denominator

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5 0
3 years ago
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If a right triangle has a hypotenuse equal to 17 and a leg equal to 15, find the third side.
Yanka [14]
Use the pythagorean theorem a.k.a{a}^{2} +  {b}^{2}  =  {c}^{2}
c is the hypotenuse while a & b are the legs
{15}^{2}   +  {b}^{2} =  {17}^{2}
225 + {b}^{2} = 289
subtract 225 from 289
{b}^{2}  = 64
square root both b and 64
the other leg is equal to 8
8 0
3 years ago
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