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Bogdan [553]
3 years ago
14

Combine the like terms : 3x +4.89xy +15y+30y-12x+9.37

Mathematics
1 answer:
finlep [7]3 years ago
3 0

Answer:3x-12x+15y+30y+4.89xy+9.37

-9x+4.89xy+45y+9.37

Step-by-step explanation:

Just place your like terms, then solve step by step, DONT RUSH!

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A bag contains 40 marbles there are 26 blue five Green five red to yellow and two black marbles without looking Layla reaches in
DENIUS [597]

10 is the answer.

I think



3 0
4 years ago
Please answer this correctly
GREYUIT [131]
0 Minutes 18 Seconds
3 0
3 years ago
Suppose you have 20 coins that total $4.some coins are nickles and sime are quarters .which of the following pairs of equations
Monica [59]
So 1 nickle=5 cents
1 quarter=25 sents

q=number of quarters
n=number of nickles so

total is
q+n=20
5n+25q=400 (since 100 cents=1 dollar and 4 dollares=400 cents)

SO THE 2 EQUATIONS WOULD BE
n+q=20
5n+25q=400

so q+n=20
subtract q from both sides
n=20-q
subsitute 20-q for n in the second equation
5(20-q)+25q=400
distribute
100-5q+25q=400
add like terms
100+20q=400
subtract 100 from both sides
20q=300
divide both sides by 20
q=15

thhere are 15 quarters

subsitute 15 for q in first equation

15+n=20
subtract 15 from both sides
n=5

5 nickles
15 quarters
4 0
3 years ago
The perimeter of a retangular pool is 360 inches the length is 8 inches longer than the width find the dimensions of the pool
White raven [17]
360=2w+2l
l=8+w

Substitute for l
360=2w+2(8+w)
360=2w+16+2w
360=4w+16
344=4w
86=w

Plug in the w value
l=8+(86)
l=94

Final answer: Length-94 inches, Width-86 inches
4 0
3 years ago
The mean breaking strength of yarn used in manufacturing drapery material is required to be at least 100 psi. Past experience ha
Aleks04 [339]

Answer:

Step-by-step explanation:

Given that:

Mean μ= 100

standard deviation σ = 2.6

sample size n = 9

sample mean X = 100.6

The null hypothesis and the alternative hypothesis can be computed as follows:

H_o : \mu \leq 100

H_1 :\mu > 100

The numerical value for the test statistics is :

z = \dfrac{x - \mu}{\dfrac{\sigma}{\sqrt{n}}}

z = \dfrac{100.6- 100}{\dfrac{2.6}{\sqrt{9}}}

z = \dfrac{0.6}{0.8667}

z = 0.6923

At  ∝ = 0.05

t_{\alpha/2 } = 0.025

The critical value for the z score = 0.2443

From the z table, area under the curve, the corresponding value which is less than the significant level of 0.05 is 1.64

P- value =  0.244

c> If the true population mean is 101.3 ;

Then:

z = \dfrac{x - \mu}{\dfrac{\sigma}{\sqrt{n}}}

z = \dfrac{101.3- 100.6}{\dfrac{2.6}{\sqrt{9}}}

z = \dfrac{0.7}{0.8667}

z = 0.808

From the normal z tables

P value  =  0.2096

3 0
3 years ago
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