Answer:
triangle A= 1/2bh
1/2(18)(14)= 126
semi circle 3.14(9)^2 divided by 2 = 127.17
Triangle Area plus semi circle Area = 126+127.17= 253.17
Answer:
20
Step-by-step explanation:
Assuming that the equation is x³ = 64, that can be solved by putting cube root on both sides like so: ∛(x³) = ∛64, which simplifies to <em>x = 4</em>.
Plugging that into our expression gives us <em>4² + 4</em>, which is 20.
Answer:
Grade B score:
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 73.3
Standard Deviation, σ = 9.7
We are given that the distribution of score on test is a bell shaped distribution that is a normal distribution.
Formula:
B: Scores below the top 5% and above the bottom 62%
We have to find the value of x such that the probability is 0.62
Calculation the value from standard normal z table, we have,
We have to find the value of x such that the probability is 0.05
Calculation the value from standard normal z table, we have,
Thus, the numerical value of score to achieve grade B is
9514 1404 393
Answer:
y = 38x
Step-by-step explanation:
The constant of proportionality (k) is the value of y when x=1. The table shows that to be 38. Then the equation is ...
y = kx
y = 38x
Answer:
D) 20.
Step-by-step explanation:
First find the value of x using Pythagoras theorem:
10^2 = x^2 + (2x)^2
5x^2 = 100
x^2 = 20
x = √20
= 2√5.
So the area of triangle
= 1/2 * base * height
= 1/2 * 2x * x
= x^2
= (2√5)^2
= 20.
