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Tems11 [23]
4 years ago
7

Divide 7/24 by 35/48 and reduce the quotient to the lowest fraction

Mathematics
1 answer:
tiny-mole [99]4 years ago
4 0
\frac{7}{24} ÷ \frac{35}{48}
Multiply \frac{7}{24} by the reciprocal of \frac{35}{48}, which is \frac{48}{35}

=\frac{7}{24} × \frac{48}{35}
=\frac{336}{840}

We can simplify it further:
The greatest common factor here is 168
\frac{336/168}{840/168}

=\frac{2}{5}
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The additional cost per month of a sunroof, spoiler and stereo is represented by three consecutive even integers, respectfully.
lesya [120]

Answer:

16

Step-by-step explanation:

First of all, I think it was "respectively", not "respecfully", =))). A noticeable point.

From the problem, three item's costs are represented by three consecutive even integer.

Thus, we can call cost of spoiler is x, sunroof is x-2, stereo is x + 2. It is conditioned that x is an even number.

Since the sum of the three is 48, we have

(x-2) + x + (x+2) = 48

x+x+x -2 +2 = 48

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x=16

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3 years ago
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y + 15 ≤ -19

y ≤ -19 - 15

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5 0
4 years ago
Devin brought his snail collection to school. He has 10 snails. How could he put them into 2 tanks so two classes could see them
monitta
10 / 2 = 5 snails each

10 = 8 (snails in one) + 2 (snails in the other)

3 + 7 = 10

4 + 6 = 10

5 + 5 = 10

If you go from 5 snails per tank and you want to add, you go up with one number and down with the other each time you write the problem a different way, but the sum cannot be over 10. If you multiply, then you know you have 10 snails and only two tanks. Doing mental math, you should be able to find out that 2 times 5 is 10. If you want to divide, you can basically do the opposite, which would be 10 divided by 2, and the answer is 5.

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6 0
4 years ago
The null and alternative hypotheses for a test are given, as well as some information about the actual sample and the statistic
anastassius [24]

Answer:

H_0: p=0.5, \,H_a: p>0.5 Right-tail test

H_0: p=0.5, \,H_a: p\neq0.5  Two-tailed test

Step-by-step explanation:

The question is incomplete. The statements about the null and alternative hypothesis are missing.

H_0: p=0.5, \,H_a: p>0.5

This is a right-tail test, as the rejection region is on the right side of the distribution.

H_0: p=0.5, \,H_a: p\neq0.5

This a two-tailed test, because the rejection region is on both extremes of the distribution.

8 0
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