Answer:
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This was the example answer. Hope this helps!! HAVE AN AMAZING DAY!
<u>Answer</u>
2,268
<u>Explanation</u>
<u>
</u>
<u>By grouping 378 ca</u>n be written as,
378 = 300 + 70 + 8
6× 378 = 6 × (300 + 70 + 8)
= (6×300)
+ (6×70) + (6×8)
= 1800
+ 420 + 48
= 2,268
Step-by-step explanation:
One year is 12 months. 12 mm is 1.2 cm.
Write and solve a proportion
1.2 cm / 4 months = x / 12 months
x = 3.6 cm
Answer:
Part c: Contained within the explanation
Part b: gcd(1200,560)=80
Part a: q=-6 r=1
Step-by-step explanation:
I will start with c and work my way up:
Part c:
Proof:
We want to shoe that bL=a+c for some integer L given:
bM=a for some integer M and bK=c for some integer K.
If a=bM and c=bK,
then a+c=bM+bK.
a+c=bM+bK
a+c=b(M+K) by factoring using distributive property
Now we have what we wanted to prove since integers are closed under addition. M+K is an integer since M and K are integers.
So L=M+K in bL=a+c.
We have shown b|(a+c) given b|a and b|c.
//
Part b:
We are going to use Euclidean's Algorithm.
Start with bigger number and see how much smaller number goes into it:
1200=2(560)+80
560=80(7)
This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.
Part a:
Find q and r such that:
-65=q(11)+r
We want to find q and r such that they satisfy the division algorithm.
r is suppose to be a positive integer less than 11.
So q=-6 gives:
-65=(-6)(11)+r
-65=-66+r
So r=1 since r=-65+66.
So q=-6 while r=1.
Answer:
Independent Variable: Number of hours
Dependent Variable: Cost
Equation: C = 2x + 6
Step-by-step explanation:
The independent variable (x) is the variable that is manipulated. In this instance, that would be the number of hours a person rents out the bike.
The dependent variable (C) is the variable that is manipulated depending on the value of the independent variable. In this instance, that would be the total cost for renting the bike.
The total equation would be C = 2x + 6. The coefficient, 2, represents the charge of $2 per hour and the 6 represents the starting charge of $6.
