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Irina-Kira [14]
3 years ago
8

I have a question for yall, im doing a sample work in geometry and its like this

Mathematics
1 answer:
Rudiy273 years ago
6 0
The appropriate thing to do is what you would do with any math.
• Study the reference material and examples you are given, making sure you understand where the formulas apply and how they are used.
• Memorize the formulas you cannot derive easily based on the understanding you have.
• Work homework and extra problems until you can apply the formulas quickly and easily to any problem to which they are relevant.

_____
The distance formula is based on the Pythagorean theorem. For a right triangle of side lengths a and b and hypotenuse c, the Pythagorean theorem tells you
  c² = a² + b²
Taking square roots, you get
  c = √(a² + b²)

When "a" and "b" are the differences of coordinates in the Cartesian plane, this becomes the distance formula:
  d = √((x₂-x₁)² + (y₂-y₁)²)



You can arrive at the midpoint formula a number of ways. I find it convenient to remember that the coordinates of a midpoint are simply the average of the coordinates of the end points. That is,
  for midpoint M = (mx, my), and endpoints A = (ax, ay), and B = (bx, by)
  M = (A+B)/2
  (mx, my) = ((ax +bx)/2, (ay +by)/2)
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Tammy rents an apartment close to her school campus. The amount that she spends on rent is given by the equation r = 355m, where
inna [77]

answer is c because if it's not a and b then the only answers will be c and d and d is the same as the number so it's c

8 0
3 years ago
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
Read 2 more answers
Help please i need to know this so i get a good grade.
ZanzabumX [31]

Answer:

The answer is -11/12

5 0
2 years ago
The diagram below shows the results of a survey of young-adults in New York State and their musical preferences.
OLga [1]
The answer is d im not sure thi
8 0
3 years ago
Which equation shows y+15=3x in standard form?
Morgarella [4.7K]
Rearranging  y + 15 = 3x we have
3x - y = 15

so its none of them
8 0
2 years ago
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