V/199 is between...?

Mathematics

1 answer:

MissTica3 years ago

7 0

I think E but I’m probably wrong???

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Find 20% of 120. Show work please.

icang [17]

Answer:

Step-by-step explanation:

When you are finding a percent of something, you need to move the decimal over to the left twice in the percentage. Like this:

20% = .20

Then, just multiply that by the number you are trying to find the percent of.

.20 x 120 = 24

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3 years ago

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You and a friend go to super taco for lunch. You order three soft tacos and three burritos and your bill totals $11.25. Your fri

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Soft tacos are going to be $1.25, and burritos are going to be $2.50

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Jennifer and Callie are training for a marathon. Jennifer has run m miles, and Callie has run 3 times as many as Jennifer. The e

galben [10]

What’s the question,

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3 years ago

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Assuming that the heights of college women are normally distributed with mean 64 inches and standard deviation 1.5 inches, what

professor190 [17]

Answer:

15.74% of women are between 65.5 inches and 68.5 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 64, \sigma = 1.5$