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marishachu [46]
3 years ago
9

4^5 write verbal expression

Mathematics
2 answers:
Aleksandr [31]3 years ago
5 0

Four to the fifth power (or to the power of 5)

Mekhanik [1.2K]3 years ago
4 0

Answer: Four to the Fifth Power

Step-by-step explanation: A verbal expression is when you give a word to word written response to the expression or equation.

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Please and thankyou (:
den301095 [7]

Let's evaluate the ratio test:

\dfrac{a_n}{a_{n-1}}=\dfrac{3^{n+1}}{3n+1}\cdot\dfrac{3(n-1)+1}{3^n}=\dfrac{3\cdot3^n}{3n+1}\cdot\dfrac{3n-2}{3^n} = \dfrac{9n-6}{3n+1}

The limit as n \to\infty of this quantity is 3, which is more than 1. So, the series diverges.

6 0
4 years ago
Solve for x<br> 9x= 1/2(20x-8)
LenKa [72]

Answer:

4

Step-by-step explanation:

9x=10x-4

x=4

3 0
4 years ago
Read 2 more answers
Factor 3x² - 2x + 6​
aalyn [17]

Answer:

sorry this does not factor out

Step-by-step explanation:

5 0
4 years ago
On the basis of data collected during an experiment, a biologist found that the growth of a fruit fly population (Drosophila) wi
Ket [755]

Answer:

(a). 15

(b). 78

Step-by-step explanation:

Growth of the population of a fruit fly is modeled by

N(t) = \frac{600}{1+39e^{-0.16t} }

where t = number of days from the beginning of the experiment.

(a). For t = 0 [Initial population]

N(0) = \frac{600}{1+39e^{-0.16\times 0} }

       = \frac{600}{1+39}

       = \frac{600}{40}

       = 15

Initial population of the fruit flies were 15.

(b).Population of the fruit fly colony on 11th day.

N(11) = \frac{600}{1+39e^{-0.16\times 11} }

       = \frac{600}{1+39e^{-1.76} }

       = \frac{600}{1+39\times 0.172 }

       = \frac{600}{1+6.71}

       = \frac{600}{7.71}

       = 77.82

       ≈ 78

On 11th day number of fruit flies colony were 78.

3 0
4 years ago
In general, the value measured by the horizontal axis is called the_______<br> variable.
azamat
Independent variable

which is the x axis the “horizontal axis
8 0
3 years ago
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