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Anvisha [2.4K]
3 years ago
6

15) The diameter of a cylinder is 12 and height is 11. Find the surface area of the figure. ​

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

A=640.88

Step-by-step explanation:

if the diameter is 12, the radius , r=12/2=6

we have r=6, h=11

Surface area, A= 2πrh+2π r^2

A=2*3.14*6*11+2*3.14*(6)^2=640.88

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What is -13 equal to
iogann1982 [59]
The answer is positive 13
8 0
3 years ago
The area of a parallelogram 33 square cm its base is 6 cm what is the height of the parallelogram​​
Greeley [361]

Answer:

Height=5.5 cm

Step-by-step explanation:

area pf parallelogram = B x H

33 = 6 x H

H=5.5 cm

4 0
3 years ago
How do you divide decimals? Ex: 3.6÷0.5 plz help!!
KiRa [710]

here's the way that i learned it:

convert them to mixed fractions and then go from there.

3.6 = 36/10 0.5 = 1/2

right now our problem looks like this: 36/10 ÷ 1/2 =

okay, so i learned the method keep it, switch it, flip it.

keep the first fraction in the equation, 36/10

switch the division sign to multiplication ÷ ⇒ ×

switch the numbers on the second fraction  1/2 ⇒ 2/1

okay, so our equation looks like this now:

36/10 x 2/1

okay, so now multiply across. (multiply the top numbers together and the bottom numbers together)

72/10

latly, we need to convert back to a decimal. divide the top number by the bottom one.

to do this, divide the top number by the bottom number

72/10

7.2

<em>i hope this was helpful. this is how i learned dividing with decimals, so it might be kinda complicated. if you still need help, let me know :)</em>

3 0
3 years ago
I don’t know how to solve this
grandymaker [24]
Area of big rectangle =8x7=56cm²
area of small rectangle =5x4=20cm²
hence area of shaded region=56-20=36cm²
7 0
3 years ago
Read 2 more answers
Circuit Training If sin0 =1 and 0 &lt;0&lt; π find 0.
valkas [14]

Answer:

\theta = \frac{\pi}{2}

Step-by-step explanation:

Given

\sin(\theta) = 1

0 < \theta < \pi

Required

Find \theta

0 < \theta < \pi implies that \theta is between 0 and 180 degrees

\sin(\theta) = 1

Take arcsin of both sides

\theta = sin^{-1}(1)

This gives:

\theta = \frac{\pi}{2}

Convert to degrees

\theta = \frac{\pi}{2} * \frac{180}{\pi}

\theta = 90

We have:

0 < \theta < \pi or 0 < \theta < 180

To get other values of \theta

We use:

\sin(\theta) = \sin(180 - \theta)

Substitute: \theta = 90

\sin(90) = \sin(180 - 90)

\sin(90) = \sin(90)

<em>This means that there are no other values of </em>\theta<em> in the given range</em>

7 0
3 years ago
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