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4 years ago

6

An isosceles triangle has two sides of equal length, a, and a base, b. The perimeter of the triangle is 15.7 inches, so the equa

tion to solve is 2a + b = 15.7. Which lengths make sense for possible values of b? Check all that apply.

2 answers:

Sunny_sXe [5.5K]4 years ago

8 0

0.5in and 2in just did that question

sineoko [7]4 years ago

6 0

It.5 and 2 guys its c and d on enguinuity

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How many variables should an experiment test at a time

Llana [10]

Answer:

One

Step-by-step explanation:

<em>Testing only one variable at a time lets you analyze the results of your experiment to see how much a single change affected the result. If you're testing two variables at a time, you won't be able to tell which variable was responsible for the result.</em>

<em>Hope this helps,</em>

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3 years ago

It won't let me get passed unless I watch a video and the video doesn't work

allochka39001 [22]

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4 years ago

Hannah estimates the ribbon is 100 cm long. The actual length of the ribbon is 125 cm. What is the percent error of Hannah's mea

Nikolay [14]

Answer: -20

percent error= amount of error/actual value * 100

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3 years ago

A study of king penguins looked for a relationship between how deep the penguins dive to seek food and how long they stay underw

zepelin [54]

Answer:

(1)0.0138

(2)A. If the depth of the dive is increased by one meter, it adds 0.0138 minutes to the time spent under water.

Nos 3-12: See Explanation

Step-by-step explanation:

Given the regression equation for the relation of dive duration (DD) to depth (D).

$DD = 2.69 + 0.0138D\\$Where: Duration DD is measured in minutes\\epth D is in meters.$

(1)The slope of the regression lie =0.0138

(2)

When D=1, DD = 2.69 + 0.0138(1)=2.7038

When D=2, DD = 2.69 + 0.0138(2)=2.7176

2.7176-2.7038=0.0138

Therefore, If the depth of the dive is increased by one meter, it adds 0.0138 minutes to the time spent under water.

(3) When depth, D =200 meters

DD = 2.69 + 0.0138(200)=5.45 Minutes

(4) When depth, D =210 meters

DD = 2.69 + 0.0138(210)=5.588 Minutes

(5) When depth, D =220 meters

DD = 2.69 + 0.0138(220)=5.726 Minutes

(6) When depth, D =230 meters

DD = 2.69 + 0.0138(230)=5.864 Minutes

(7) When depth, D =240 meters

DD = 2.69 + 0.0138(240)=6.002 Minutes

(8) When depth, D =150 meters

DD = 2.69 + 0.0138(150)=4.76 Minutes

(9) When depth, D =160 meters

DD = 2.69 + 0.0138(160)=4.898 Minutes

(10) When depth, D =170 meters

DD = 2.69 + 0.0138(170)=5.036 Minutes

(11) When depth, D =180 meters

DD = 2.69 + 0.0138(180)=5.174 Minutes

(12) When depth, D =190 meters

DD = 2.69 + 0.0138(190)=5.312 Minutes

7 0

3 years ago

Given f(x) = −9x5 − x4 + 3x3 − 8 and g(x) = −9x5 − 3x3 − 9x2 + 7, find and simplify f(x) − g(x)

KatRina [158]

F(x) − g(x) =  −9x^5 − x^4 + 3x^3 − 8 − (<span>−9x^5 − 3x^3 − 9x^2 + 7)
</span>f(x) − g(x) =  −9x^5 − x^4 + 3x^3 − 8 + 9x^5 + 3x^3 + 9x^2 − 7
f(x) − g(x) = − x^4 + 6x^3 +  9x^2 - 15
hope it helps

4 0

3 years ago