Look at the axis graph. If both of the coordinates are negative, it would be in quadrant lll. If you go over to the x-axis, you would be in quadrant lV, or 4.
(5, 3) (-6, 3) The slope is 0 Slope = m = (Y2<span> -Y</span>1<span>) </span>÷<span> (X</span>2<span> -X</span>1<span>) (Y2 -Y1)=0 SO, the distance is just the difference in the x values. distance = 5 --6 = 11