Number set:
18, 36, 900
GCF:
9
Y = cos(x)
sqrt(3)/2 = cos(30º)
dy = -sin(x)*dx
dy = -sin(30º)*(pi/180) = (1/2)*(pi/180)
y + dy = cos(x) - sin(x)dx
y + dy = sqrt(3)/2 - (1/2)*(pi/180) = 0.8573
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A=2(wh+lw+lh)
l=8m
w=3m
h=2m
A=2((3m)(2m)+(8m)(3m)+(8m)(2m))
A=2((6m)+(24m)+(16m))
A=2(46m)
A=92m
Area is 92m
Answer: 
Step-by-step explanation:
The confidence interval for population mean is given by :-
, where
is the sample mean and ME is the margin of error .
Given : The sample mean : 
Margin of error : 
Then , the range of values (confidence interval) likely to contain the true value of the population parameter will be :-

Hence, the range of values likely to contain the true value of the population parameter = 
Answer:
2 1/2
Step-by-step explanation:
Hope this helps :P
Have a great day!