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likoan [24]
3 years ago
11

Write a equation of a line that is perpendicular to y = -2/7x+9and pass through point (4,-6)

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0

Answer:

y = 7/2x - 20.

Step-by-step explanation:

The slope of the given line is -2/7,  therefore the slope of the line perpendicular to it is  - 1/ -2/7 = 7/2.

When x = -4, y = -6  so we substitute x1 = 4, y1 = -6 and m ( the slope) = 7/2 in the point slope form of a line:

y - y1 = m(x - x1)

y - (-6) = 7/2(x - 4)

y + 6 = 7/2x - 14

y = 7/2x - 20.

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HELPPP
Juli2301 [7.4K]

Answer:

slope (m) = -\frac{3}{2}

Step-by-step explanation:

We can find the slope (m) by using coordinate pairs of any 2 points located along the slope of the line that we have on the graph.

This, let's use the coordinate pairs at:

x = -4, y = 2 (-4, 2) => (x2, y2)

x = 0, y = -4 (0, -4) => (x1, y1)

slope (m) = \frac{y2 - y1}{x2 - x1}

slope (m) = \frac{2 -(-4)}{-4 - 0}

slope (m) = \frac{2 + 4}{-4 - 0}

slope (m) = \frac{6}{-4}

slope (m) = \frac{3}{-2}

slope (m) = -\frac{3}{2}

4 0
2 years ago
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Kobotan [32]

Answer:

2 and 6

Step-by-step explanation:

2+6=8. 6-2=4.

5 0
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Answer:

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