The first example has students building upon the previous lesson by applying the scale factor to find missing dimensions. This leads into a discussion of whether this method is the most efficient and whether they could find another approach that would be simpler, as demonstrated in Example 2. Guide students to record responses and additional work in their student materials.
§ How can we use the scale factor to write an equation relating the scale drawing lengths to the actual lengths?
!
ú Thescalefactoristheconstantofproportionality,ortheintheequation=or=!oreven=
MP.2 ! whereistheactuallength,isthescaledrawinglength,andisthevalueoftheratioofthe drawing length to the corresponding actual length.
§ How can we use the scale factor to determine the actual measurements?
ú Divideeachdrawinglength,,bythescalefactor,,tofindtheactualmeasurement,x.Thisis
! illustrated by the equation = !.
§ How can we reconsider finding an actual length without dividing?
ú We can let the scale drawing be the first image and the actual picture be the second image. We can calculate the scale factor that relates the given scale drawing length, , to the actual length,. If the actual picture is an enlargement from the scale drawing, then the scale factor is greater than one or
> 1. If the actual picture is a reduction from the scale drawing, then the scale factor is less than one or < 1.
Scaffolding:
A reduction has a scale factor less than 1, and an enlargement has a scale factor greater than 1.
Lesson 18: Computing Actual Lengths from a Scale Drawing.
Like wat is it like i need was you need to show me your Question so i know what you talking about
you just have to move the decimal point 9 places to the right thats an easy trick to remember 1849900000
Answer:
1. D
2. y = 15.50x + 450
Step-by-step explanation:
1. Since it is a function, the missing pair can't repeat input values with different output, therefore only option D is unique so is the correct choice.
2. x > (y - 450)/ 15.50
i) Rita gets paid $450 per week.
ii) She gets $15.50 for every new membership she sells.
iii) let y represent the total pay per week.
iv) let x represent the number of new memberships sold.
v) the equation representing total pay is y = 15.50x + 450.
vii) therefore the equation that represents a higher rate of membership sold is given by x > (y - 450)/ 15.50
