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4 years ago

15

What is 3 thousands / 10 in unit form

2 answers:

Marrrta [24]4 years ago

3 0

I think that it is 300

AnnZ [28]4 years ago

3 0

I think it would be 300

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F(x)= -2x + 2; Find f(5)

zhuklara [117]

If f(x) = -2x + 2, f(5) can be found by substituting in the value 5 for x in the equation:

f(5) = - 2(5) + 2

Our first step in simplifying this expression is to perform the multiplication as outlined by the order of operations (PEMDAS).

f(5) = -10 + 2

Finally, we must get our final answer by adding together the remaining terms.

f(5) = -8

Hope this helps!

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4 years ago

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Brilliant_brown [7]

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3 years ago

Factor completely. wait for photo

rjkz [21]

Apparently there's no solution?? i tried solving it, and i also used a special calculator, but no solution came up

4 0

3 years ago

The function f(x) = 1/2 x + 3/2 is used to complete this table.

Mrac [35]

Answer:

a) f(-1/2) = -2 is NOT TRUE.

b) f(0) =3/2 is TRUE.

c) f(1) = -1 is NOT TRUE.

d) f(2) = 1 is NOT TRUE.

e) f(4) = 7/2 is TRUE.

Step-by-step explanation:

Here, the given function is $f(x) = (\frac{1}{2}) x+\frac{3}{2}$

Now, checking for each values for the given function:

a) Putting x = (-1/2):

$f(\frac{-1}{2} ) = (\frac{1}{2})(\frac{-1}{2} ) +\frac{3}{2} = \frac{-1}{4} + (\frac{3}{2} )\\\implies f(x) = \frac{-1 + 6}{4} = (\frac{5}{4} )$

and (5/4) ≠ -2

Hence, f(-1/2) = -2 is NOT TRUE.

b)Putting x = 0 :

$f(0) = (\frac{1}{2})(0 ) +\frac{3}{2} = (\frac{3}{2} )$

Hence, f(0) =3/2 is TRUE.

c) Putting x = 1:

$f(1 ) = (\frac{1}{2})(1 ) +\frac{3}{2} = \frac{1}{2} + (\frac{3}{2} )\\\implies f(x) = \frac{3 + 1}{2} = (\frac{4}{2} ) = 2\implies 2 \neq -1$

Hence, f(1) = -1 is NOT TRUE.

d)Putting x = 2:

$f(2 ) = (\frac{1}{2})(2 ) +\frac{3}{2} = 1+ (\frac{3}{2} )\\\implies f(x) = \frac{2 + 3}{2} = (\frac{5}{2} )$

and (5/2) ≠ 1

Hence, f(2) = 1 is NOT TRUE.

e)Putting x = 4:

$f(4 ) = (\frac{1}{2})(4 ) +\frac{3}{2} = 2 + (\frac{3}{2} )\\\implies f(x) = \frac{4 + 3}{2} = (\frac{7}{2} )$

Hence, f(4) = 7/2 is TRUE.

4 0

3 years ago

Can someone please help me with this

k0ka [10]

Answer: $3x^6+x^5-x^4-6x^3+x^2+3x-1$

Step-by-step explanation:

(3x^2+x-1)(x^4-2x+1)

=3x^6-6x^3+3x^2+x^5-2x^2+x-x^4+2x-1

=3x^6+x^5-x^4-6x^3+x^2+3x-1

Hope this helps!! :)

Please let me know if you have any question

5 0

3 years ago

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