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kaheart [24]
3 years ago
9

REASONING A drone that costs $129.50 is discounted 40%. The next month, the sale price is discounted an additional 60%. Is the d

rone now "free"? yes no Question 2 If the drone is "free", explain. 0 / 10000 Word Limit Question 3 If the drone is not "free", find the sale price. The sale price is $ .
Mathematics
1 answer:
marishachu [46]3 years ago
6 0

Answer:

Not "free". The new sales price is $31.08

Step-by-step explanation:

Given that the costs of the drone ($129.50) is discounted 40%, the new price after the discount

= $129.50 - 40% * $129.50

= $129.50 - $51.80

= $77.70

Given that the  next month, the sale price is discounted an additional 60%., the new price after this discount

= $77.70 - 60% * $77.70

= $77.70 - $46.62

= $31.08

From above, the drone is not "free". The new sales price is $31.08

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Find the derivative of g(t)=t2+5t at t=7 algebraically.
Elanso [62]

The power rule applies to each term.

... (d/dt)(t^n) = n·t^(n-1)

... g'(t) = 2t +5

... g'(7) = 2·7 +5 = 19

3 0
4 years ago
Help please? It would help a lot :)
timofeeve [1]
6.
a. P(2 or 4) is the probability of rolling either a 2 or a 4 on the die.
P(2 or 4) is equal to P(rolling a 2) + P(rolling a 4)
1/6 + 1/6 = 2/6 = 1/3

b. P(greater than 2) is equal to P(3) + P(4) + P(5) + P(6)
1/6 + 1/6 + 1/6 + 1/6 = 4/6 = 2/3

7. The probability of getting a head is 1/2. If you toss the coin two times, there are four different possibilities. HH, TT, HT, or TH. The answer would be 1/4, you get that by multiplying 1/2 by 1/2 again.
3 0
3 years ago
Braniliest
Paul [167]

Answer:

D. 28

Step-by-step explanation:

This answer is it because 28 is greater than 25.

3 0
3 years ago
How much mquarts are in 7 liters
IrinaK [193]

Answer:

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7 0
3 years ago
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Just tell me the perimeter and area plz. will mark as brainliest.
Jet001 [13]
Given that the height of the triangle portion of the enclosure is 28 ft and the base is 22 ft, we can find the two outer sides' lengths using Pythagorean Theorem:

a^2 + b^2 = c^2

The legs of the right triangle formed by the height, half the base, and one of the outer walls are 28 and 11. So:

28^2 + 11^2 = c^2

784 + 121 = c^2

c =  \sqrt{905}  or about 30.08 ft

This is the length of both linear sides of the enclosure.

Next, to find the bottom side's length, we need to figure out half of the circle's circumference. We know that:

C = 2 \pi r

So the other side's length is:

\frac{1}{2} (22) \pi =11 \pi

Or about 34.56 ft

The perimeter is:

2(30.08) + 34.56 = 94.72 ft

Next, to find the area of the triangle portion of the enclosure, we must use:

A =  \frac{1}{2}bh

\frac{1}{2} (22)(28) = 308 ft^2

The area of a circle is:

A =  \pi r^2

So the semi-circle portion of the enclosure has an area of:

\frac{1}{2}  \pi (11)^2 =  \frac{121 \pi }{2}

or about 190.07 ft^2

The total area of:

308 + 190.07 = 498.07 ft^2
5 0
3 years ago
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