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Korvikt [17]
3 years ago
12

Solve for x: (3a−b)/(x−b)=1/(x+1) ,if a≠( b+1)/3

Mathematics
1 answer:
frozen [14]3 years ago
4 0

Answer:

Step-by-step explanation:

\frac{(3a-b)}{(x-b)}=\frac{1}{(x+1)}\\\\(3a-b)*(x+1)=1*(x-b)\\\\

Use FOIL method

3a*x + 3a*1 - b*x -b*1 = x - b

3ax + 3a -bx - b = x -b

3ax - bx -x + 3a - b = -b

x*( 3a - b - 1) + 3a - b = -b

x*( 3a - b - 1) = - b - 3a + b

x*( 3a - b - 1) = -3a

x=\frac{-3a}{( 3a - b - 1)}

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