For a p-type silicon in which the dopant concentration na = 5x10^18/cm^3

Mathematics

1 answer:

slavikrds [6]2 years ago

8 0

For a p-type silicon in which the dopant concentration N A = 5 × 10^ 18 /cm^3 , find the hole.

For a p-type silicon in which the dopant concentration NA= 5×1018/cm^3, find the hole and electron concentrations

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In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the popu

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$19.6-2.42\frac{5.8}{\sqrt{42}}=17.43$

$19.6+2.42\frac{5.8}{\sqrt{42}}=21.77$

And the best option for this case would be:

a. (17.5, 21.7)

Step-by-step explanation:

Information given

$\bar X= 19.6$ represent the sample mean

$\mu$ population mean

$\sigma= 5.8$ represent the population deviation

n=42 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.98 or 98%, the significance would be $\alpha=0.02$ and $\alpha/2 =0.1$ , and the critical value would be $t_{\alpha/2}=2.42$