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3 years ago

For a p-type silicon in which the dopant concentration na = 5x10^18/cm^3

Mathematics

1 answer:

slavikrds [6]3 years ago

8 0

For a p-type silicon in which the dopant concentration N A = 5 × 10^ 18 /cm^3 , find the hole.

For a p-type silicon in which the dopant concentration NA= 5×1018/cm^3, find the hole and electron concentrations

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A community college has a math placement exam that has a mean of 65 and a standard deviation of 8.2. If a student takes the exam

Marat540 [252]

Answer:

The score that cuts off the bottom 2.5% is 48.93.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 65, \sigma = 8.2$

What is the score that cuts off the bottom 2.5%

This is X when Z has a pvalue of 0.025, so X when Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{X - 65}{8.2}$

$X - 65 = -1.96*8.2$

$X = 48.93$

The score that cuts off the bottom 2.5% is 48.93.

8 0

3 years ago

Read 2 more answers

What is the true solution to the equation below? ln e^lnx^2=2 ln 8?

arlik [135]

$x\ \textgreater \ 0\\\\
\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8\\
\ln x+\ln x^2=\ln 8^2\\
\ln (x\cdot x^2)=\ln 64\\
\ln x^3=\ln 64\\
x^3=64\\
x=4\Rightarrow \text {B}
$

6 0

3 years ago

Read 2 more answers

Explain why a graph that fails the vertical-line test does not represent a function. Be sure to use the definition of a function

ArbitrLikvidat [17]

Explanation:

A function is a relationship where any one x-value/input only has <u>one </u>corresponding y-value/output. (note: a y-value can have multiple x-values).

> This can be called "assigning one y-value to every x element".

The vertical line test places a line that would connect all y-values of an x-value (that is, if it were to have multiple y-values). If multiple points can be found along the vertical line, it is, therefore, by the definition of a function, not a function. (Because an x-value will have more than one y-value).

So, a graph that fails the vertical-line test does not represent a function because an x-value will correspond with more than one y-value.

hope this helps!!

4 0

2 years ago

A scale drawing of a building is one foot to 1/4 inch. What is the actual length of the building if the scale drawing shows that

Rom4ik [11]

$1\quad foot\quad :\quad \frac { 1 }{ 4 } \quad inch\\ \\ 4\quad \cdot \quad 1\quad foot\quad :\quad \frac { 1 }{ 4 } \quad inch\quad \cdot \quad 4\\ \\ 4\quad feet\quad :\quad 1\quad inch$

This means that:

$4\quad feet\quad :\quad 1\quad inch\\ \\ \frac { 27 }{ 2 } \cdot \quad 4\quad feet\quad :\quad \frac { 27 }{ 2 } \cdot \quad 1\quad inch\\ \\ \frac { 108 }{ 2 } \quad feet\quad :\quad \frac { 27 }{ 2 } \quad inches\\ \\ 54\quad feet\quad :\quad \frac { 27 }{ 2 } \quad inches\\ \\$

13 + 1/2 inches is the same as 54 feet

4 0

3 years ago

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Which graph is an example of a cubic function?

AleksAgata [21]

Cubic functions usually look like an S

7 0

3 years ago