Answer:
6546 students would need to be sampled.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
The margin of error is:

The dean randomly selects 200 students and finds that 118 of them are receiving financial aid.
This means that 
90% confidence level
So
, z is the value of Z that has a p-value of
, so
.
If the dean wanted to estimate the proportion of all students receiving financial aid to within 1% with 90% reliability, how many students would need to be sampled?
n students would need to be sampled, and n is found when M = 0.01. So






Rounding up:
6546 students would need to be sampled.
I would go with option C. x, in the first equation.
The X term has a coefficient of 3, the lowest common factor amongst the 3 terms making for easy isolation of the variable.
Answer:
f(x) = { x, -5 ≤ x < 0 and 3x - 3, 1 ≤ x < 5
Step-by-step explanation:
The equation of one line is y = x
The equation of the other line is y = 3x - 3
Altogether,
f(x) = { x, -5 ≤ x < 0 and 3x - 3, 1 ≤ x < 5
Answer:
-1.9f-20
Step-by-step explanation:
-2.7f+0.8f-16-4
<em>Collect similar items</em>
-2.7f+0.8f=-1.9f
=-1.9f-16-4
<em>Subtract the numbers</em>
-16-4=-20
=-1.9f-20
The correct answer is 3.53