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3 years ago

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Each person in a group of 12 has one pet. Three people have a cat, 2 people have a dog, and the rest have a bird. What is the pr

obability of a person having a cat or a dog?

2 answers:

AVprozaik [17]3 years ago

7 0

5 out of 12.
3 cats + 2 dogs =5
12= out of everyone w a pet

katrin2010 [14]3 years ago

4 0

Answer:

63 % for cats and 37 % for dogs

Step-by-step explanation:

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The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

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3 years ago

Ram wants to work to preserve marine habitats. Which field of study would be most useful to him

Nataliya [291]

<span>Oceanography the others are other studies

</span>

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3 years ago

Read 2 more answers

Answer the picture below.

inysia [295]

Answer:

Step-by-step explanation:

function: all the points

note: x intercept is the domain, y intercept is the range

domain must paired with exact range

the domain can be more than 1, but range must be 1.

domain : 3, 5, 0 , -1, -3, -5

range: 1, 3, 4 , -3(there is 2 but we write it one) , -4

and done!

thank you!

4 0

3 years ago

Solve 5x = 2 written a afrction inits simplest form

Elden [556K]

Answer:

x = 2/5

General Formulas and Concepts:

Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Write equation</u>

5x = 2

<u>Step 2: Solve for </u><em><u>x</u></em>

Divide both sides by 5: x = 2/5

<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution</em>.

Substitute: 5(2/5) = 2
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3 years ago

Solve the triangle that has a=4.6, B=19°, A=92° (picture provided)

kolezko [41]

Answer:

Option b

Step-by-step explanation:

To solve this problem use the law of the sines.

We have 2 angles of the triangle and one of the sides.

$a = 4.6\\B = 19\°\\A = 92\°\\C = 180 -A - B\\C = 180 - 92 - 19\\C = 69\°$

The law of the sines is:

$\frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}$

Then:

$\frac{sin(92)}{4.6} = \frac{sin(19)}{b}\\\\b = \frac{sin(19)}{\frac{sin(92)}{4.6}}\\\\b = 1.5$

$\frac{sin(B)}{b} = \frac{sin(C)}{c}\\\\\frac{sin(19)}{1.5} = \frac{sin(69)}{c}\\\\c = \frac{sin(69)}{\frac{sin(19)}{1.5}}\\\\c = 4.30$

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3 years ago