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konstantin123 [22]
4 years ago
12

I dont understand how to answer this. I tried to find the second derivative. ​

Mathematics
1 answer:
Orlov [11]4 years ago
7 0

Answer:

(B) π/12 + π/6 k

Step-by-step explanation:

Points of inflection are where f"(x) = 0 and changes signs.

f(x) = cos²(3x)

f(x) = (cos(3x))²

f'(x) = 2 (cos(3x))¹ × -sin(3x) × 3

f'(x) = -6 sin(3x) cos(3x)

Using double angle formula:

f'(x) = -3 sin(6x)

f"(x) = -3 cos(6x) × 6

f"(x) = -18 cos(6x)

0 = -18 cos(6x)

0 = cos(6x)

6x = π/2 + 2πk or 6x = 3π/2 + 2πk

We can simplify this to:

6x = π/2 + πk

x = π/12 + π/6 k

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<h3>Hello there!</h3>

Here's the information given to us written out:

- 31560 total students

- 12/180 students speak 3 or more

To solve:

To solve this, use the probability from the survey of 180 students to make a reasonable estimate for the 31560 total students.

12/180 students were able to speak 3 or more languages. This proportion, of 12 students : 180 students can be adjusted.

Just like when simplifying fractions, both sides can have an operation (of multiplication or division) done to it and still be equivalent.

In this case, we want to set the side of total students to be equivalent to 31560 to get the estimated number of students that speak 3 or more languages.

To get the number to multiply both sides by:

31560 / 180 = 175 1/3 = 526/3

Now, carry out the operation - multiply both sides by that number.

12/180 = (12 * 526/3) / (180 * 526/3) = 2104 / 31560

So, out of 31560, using the same probability, around 2104 students would speak 3 or more languages.

Hope this helped!

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