You need to find the probability of Heads, Heads, Heads in 3 tosses;
P(HHH)= (1/2)(1/2)(1/2) <-- each toss has 2 possibilities and heads is one
P(HHH)=1/8
Therefore, the probability of flipping 3 heads on a fair coin is 1/8
Hope I helped :)
Answer:
0.999987
Step-by-step explanation:
Given that
The user is a legitimate one = E₁
The user is a fraudulent one = E₂
The same user originates calls from two metropolitan areas = A
Use Bay's Theorem to solve the problem
P(E₁) = 0.0131% = 0.000131
P(E₂) = 1 - P(E₁) = 0.999869
P(A/E₁) = 3% = 0.03
P(A/E₂) = 30% = 0.3
Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :




= 0.999986898 ≈ 0.999987
Answer:
15 degrees
Step-by-step explanation:
angle a= (180-90)/2=90/2=45 degrees
angle QRP = 60
Angle b = 60-45=15 degrees
Answer:
A:48 B:45
Step-by-step explanation:
There is no statements to choose from