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Mrrafil [7]
3 years ago
10

The graph shows a proportional relationship between the cost of carpet cleaning (y-axis) and the area of the carpet (x-axis).

Mathematics
2 answers:
Savatey [412]3 years ago
8 0
I think its 150 thats what i put and it said it was correct
ivolga24 [154]3 years ago
6 0

Answer: 150

Step-by-step explanation:

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15 a2 - 6ab- 8 a2+ 20 - 5ab - 31 + a2- ab
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Remove the parentheses: 15a²-6ab+8a²+20+5ab-31+a²-ab Combine like terms: 24a²-2ab-11

Answer: 24a²-2ab-11

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Find the value of x.<br><br> A.<br> 7<br> B.<br> 9<br> C.<br> 11<br> D.<br> 12
Arisa [49]
Use the law of cosines to solve for angle A. Plug your known side length values into the equation a^2 = b^2 + c^2 – 2bc cos A.

Then use the law of sines to find angle B. (Sin A/a = Sin B/b = Sin C/c).

Because the two red angles within B are congruent, divide your angle measure in half.

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I hopes this helps
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3 years ago
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What is the answer of 10% of 115%
mixer [17]

Answer:

0.115

Step-by-step explanation:

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3 years ago
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Estimate the surface area of the rectangular prism.<br> A) 28cm<br> B) 32cm<br> C) 64cm
Ede4ka [16]

Answer:

it a

Step-by-step explanation:

4 0
3 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
3 years ago
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