Y = 180 - 51 -56 = 73
x = 180 - 73 - 72 = 35
x = 35 degrees
Answer:
0.46
Step-by-step explanation:
Answer:
2630 g
Step-by-step explanation:
From the given information:
Given that:
mean (μ) = 3750 g
Standard deviation (σ) = 500
Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;
Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;
P(Z < z₁) = 0.03
Using the Excel Formula; =NORMSINV(0.03) = -1.88
z₁ = - 1.88
Using the test statistics z₁ formula:


By cross multiply, we have:
-1.88 × 500 = X - 3570
-940 = X - 3570
-X = -3570 + 940
-X = -2630
X = 2630 g
Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not
To start with, draw a line say AB.
At point B, construct 60 degrees.
Bisect the angle to get 30 degrees.
Bisect the 30 degrees to get 15 degrees.
The angle opposite the 15 degrees is 165 degrees
the answer is 1....
then after you put that up you have to take the number