Answer:
Probability that the measure of a segment is greater than 3 = 0.6
Step-by-step explanation:
From the given attachment,
AB ≅ BC, AC ≅ CD and AD = 12
Therefore, AC ≅ CD = ![\frac{1}{2}(\text{AD})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BAD%7D%29)
= 6 units
Since AC ≅ CD
AB + BC ≅ CD
2(AB) = 6
AB = 3 units
Now we have measurements of the segments as,
AB = BC = 3 units
AC = CD = 6 units
AD = 12 units
Total number of segments = 5
Length of segments more than 3 = 3
Probability to pick a segment measuring greater than 3,
= ![\frac{\text{Total number of segments measuring greater than 3}}{Total number of segments}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BTotal%20number%20of%20segments%20measuring%20greater%20than%203%7D%7D%7BTotal%20number%20of%20segments%7D)
= ![\frac{3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D)
= 0.6
Your answer is <u>12v-3.</u>
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Steps:
1. Group Like Terms. (8v-3v+7v-3)
2. Add Similar Elements. (8v-3v+7v=12v)
3. Finished. (=12v-3)
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Hope this helped :)
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