All categories

3 years ago

15p!!!!What is the percent of change from 94 to 43? round to the nearest percent

Mathematics

1 answer:

Naddika [18.5K]3 years ago

7 0

Answer:

54%

Step-by-step explanation:

The different from 94 to 43:

94 - 43 = 51

The percent of change:

51/94 = 0.54 or 54%

Answer

54%

You might be interested in

The owner of an electronics store received a shipment of MP3 players at a cost of $64.25 each. If he sells the MP3 players for $

Lostsunrise [7]

99.99 - 64.25= 35.74
35.74/64.25= 0.556=55.6% or 56% rounded

4 0

3 years ago

Solve for x. Help me out because I haven’t been paying attention all year

svet-max [94.6K]

Answer:

x = 18

Step-by-step explanation:

(whole secant) x (external part) = (whole secant) x (external part)

(6+x)6 = (8+10)* 8

6*(6+x) = 8(18)

Divide each side by 6

6+x = 8(18)/6

6+x = 8*3

6+x = 24

Subtract 6 from each side

6+x-6 =24-6

x = 18

8 0

2 years ago

2,023 nearest hundred

Oxana [17]

2,000

hope this helps

4 0

3 years ago

Read 2 more answers

Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th

Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=22 g$ is the final amount of the radioactive element

$A_{o}=800 g$ is the initial amount of the radioactive element

$t$ is the time elapsed

$h=8 min$ is the half life of the radioactive element

So, we need to substitute the given values and find $t$ from (1):

$22 g=(800 g) 2^{\frac{-t}{8 min}}$ (2)

$\frac{22 g}{800 g}=2^{\frac{-t}{8 min}}$ (3)

$\frac{11}{400}=2^{\frac{-t}{8 min}}$ (4)

Applying natural logarithm in both sides:

$ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}})$ (5)

$-3.593=-\frac{t}{8 min}ln(2)$ (6)

Clearing $t$ :

$t=41.46 min \approx 41.5 min$ This is the time elapsed

7 0

2 years ago

Please show work!!!!!!

likoan [24]

Answer:

$\frac{4\sqrt{5} }{5}$

Step-by-step explanation:

$\frac{4\sqrt{6} }{\sqrt{30} } =\frac{\sqrt{30} *4*\sqrt{6} } \sqrt{30} {\sqrt{30} } \\\\$

$\frac{4\sqrt{6*30} }{30} =\frac{4*\sqrt{180} }{30} =\frac{4*\sqrt{36*5} }{30} = \\\\\frac{4*6\sqrt{5} }{6*5} =\frac{4\sqrt{5} }{5}$

5 0

3 years ago

Read 2 more answers