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Elena-2011 [213]
3 years ago
14

Michale has a loan with a balance of $200 at 14% simple interest. If he pays the loan back in 12 equal payments, how much will b

e each payment?
Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

it would be 19 dollars a month

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Among cases of heart pacemaker malfunctions, were found to be caused by firmware, which is software programmed into the device.
alex41 [277]

Complete question is;

Among 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware, which is software programmed into the device. If the firmware is tested in three different pacemakers randomly selected from this batch of 8834 and the entire batch is accepted if there are no failures, what is the probability that the firmware in the entire batch will be accepted? Is this procedure likely to result in the entire batch being accepted?

Answer:

P(All three are not caused by firmware) = 83.84%

Probability that the entire batch will be accepted = 0.8384

Step-by-step explanation:

We are told that out of the 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware.

Thus,

Cases not caused by firmware = 8834 - 504 = 8330

So, probability of the first case not being affected by firmware is;

P(first case not caused by firmware) = 8330/8834

Also,

Probability of second case not being affected by firmware is given as;

P(second case not caused by firmware|first case not affected by firmware) = 8329/8833

Similarly,

Probability of third case not being affected by firmware is given as;

P(third case not caused by firmware|first and second not caused by firmware) = 8328/8832

Now, looking at the 3 Probabilities gotten, it is obvious that the events are not independent because the probability of occurence of one event depends on the probability of occurence of the other event.

Thus, we will make use of the general multiplication rule which is;

P(A & B) = P(B) × P(A|B)

Thus;

P(All three not caused by firmware) = P(first case not caused by firmware) × P(second case not caused by firmware|first case not affected by firmware) × P(third case not caused by firmware|first and second not caused by firmware)

Plugging in the relevant values, we have;

P(All three not caused by firmware) = (8330/8834) × (8329/8833) × (8328/8832)

P(All three are not caused by firmware) = 0.83840506679 ≈ 83.84%

6 0
3 years ago
If the probability of an events is 2/7 what must be the probability of its compliments
monitta

Answer:

The probability of its compliments = 0.7143 = 5/7

Step-by-step explanation:

The probability of an events = P= 2/7 = 0.2857

The probability of its compliments = 1-p = 1-0.2857 = 0.7143 = 5/7

6 0
3 years ago
Write an inequality for the given description. The product of -5 and an unknown number increased by 15 is less than or equal to
sesenic [268]

Answer:

-5x +15 ≤ 20

Step-by-step explanation:

7 0
3 years ago
A rectangular card has an area of 120 over 1\4 square inches. The card is 6 over 1\2 inches wide. How long is the card???? if u
Anika [276]
The area is 120/(1/4) or 120 x 4 or 480 square inches
the width is 6/(1/2) or 6 x 2 or 12 inches
to find the length, divide the area by the width
480/12= 40
40 inches
Hope this helps :)

7 0
3 years ago
Simplify each expression. Write your answers in exponential notation.
GenaCL600 [577]

\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad
a^n\implies \cfrac{1}{a^{-n}}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{36b^3}{9a^5} \right)^3\implies \left( \cfrac{4b^3}{a^5} \right)^3\implies \stackrel{\textit{distributing the exponent}}{\left(\cfrac{4^3b^{3\cdot 3}}{a^{5\cdot 3}}\right)}\implies \cfrac{64b^9}{a^{15}}

3 0
3 years ago
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