Answer:
4, 2, 1, 2, 4
Step-by-step explanation:
-2 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(-2).
f(-2) = (1/2)^-2 = 1^-2/2^-2 = 2^2/1^2 = 4/1 = 4
-1 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(-1).
f(-1) = (1/2)^-1 = 1^-1/2^-1 = 2^1/1^1 = 2/1 = 2
0 <= 0, so use the first equation, f(x) = (1/2)^x, to find f(0).
f(0) = (1/2)^0 = 1^0/2^0 = 1/1 = 1
1 > 0, so use the second equation, f(x) = 2^x, to find f(1).
f(1) = 2^1 = 2
2 > 0, so use the second equation, f(x) = 2^x, to find f(2).
f(2) = 2^2 = 4
Sure what is the question?
Set it up as a direct variation equation y/x=k where k is the constant of variation. We have values for y and x and have to find k. 18/5=k, so k=3.6. Now plug in the other given y value and use that k value to find x: y/11=3.6 or
y/11=18/5, whichever your book or teacher prefers.
Answer:
Step-by-step explanation:
The odds of the first sock being blue is:
or reduced to
The odds for the second sock being blue is:
The odds of both happening is
This can be simplified by 9 resulting in