Answer:
The answer to your question is below
Step-by-step explanation:
Data
1.- f(x) = 5x³ - 31x² - 129x + 27
a) f(9) = 5(9)³ - 31(9)² - 129(9) + 27
f(9) = 5(729) - 31(81) - 1161 + 27
f(9) = 3645 - 2511 - 1161 + 27
f(9) = 0
b.- I will use synthetic division
5 - 31 -129 + 27 9
45 126 -27
5 14 -3 0
Trinomial = 5x² + 14x - 3
Factor 5x² + 15x - 1x - 3
5x(x + 3) - 1(x + 3)
b) (x + 3)(5x - 1)
x₂ + 3 = 0 5x₃ - 1 = 0
x₂ = -3 x₃ = 1/5
c) The roots are x₁ = 9, x₂ = -3 and x₃ = 1/5
2.- f(x) = 3x² + 2x - 8 factor = 3x - 4
x + 2
3x - 4 3x² + 2x - 8
-3x² + 4x
0 +6x - 8
-6x + 8
0 Remainder
As the remainder was "0", 3x - 4 is a factor of 3x² + 2x - 8
After adding 8 students to each of 6 same-sized teams, there were 72 students altogether.
After adding an 8-pound box of tennis rackets to a crate with 6 identical boxes of ping pong paddles, the crate weighed 72 pounds.
The first situation has all equal parts, since additions are made to each team. An equation that represents this situation is 6( x + 8 ) = 72, where x represents the original number of students on each team. Eight students were added to each group, there are 6 groups, and there are a total of 72 students.
In the second situation, there are 6 equal parts added to one other part. An equation that represents this situation is 6x + 8 = 72, where x represents the weight of a box of ping pong paddles, there are 6 boxes of ping pong paddles, there is an additional box that weighs 8 pounds, and the crate weighs 72 pounds altogether.
In the first situation, there were 6 equal groups, and 8 students added to each group. 6( x + 8 ) = 72.
In the second situation, there were 6 equal groups, but 8 more pounds in addition to that. 6x + 8 = 72.
Answer:
Step-by-step explanation:
Given expression:
To simplify the expression, we will use the formula (a - b)² = a² - 2ab + b².
[Where "a and b" are the first and second term in (a - b)²]
In this case, the first term of (2x - 12)² is "2x" and the second term is "12".
![\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\small\text{First term = a = 2x; Second term = b = 12]}](https://tex.z-dn.net/?f=%5Crightarrowtail%20%282x%29%5E%7B2%7D%20-%202%282x%29%2812%29%20%2B%20%2812%29%5E%7B2%7D%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5B%5Csmall%5Ctext%7BFirst%20term%20%3D%20a%20%3D%202x%3B%20Second%20term%20%3D%20b%20%3D%2012%5D%7D)
Now, simplify the expression.
Answer:
C should be your answer if I'm not right then forgive me please.
Step-by-step explanation:
