Answer:
b. 45deg
Step-by-step explanation:
see attached
The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
Im not really good at these but i do think it is c. Sorry im not 100% sure. <span />
Answer:
1) -2x
2) 6x - 17
3) -16x
4) 3m - 5
5) 2m
6) 2x - 9
7) 9x
8) 6x + 8
Step-by-step explanation:
1) = x(7-9) = x(2) = 2x
2) x(-2+8) - 7 - 10 = x(6) - 17 = 6x - 17
3) x(-10-6) + 3 - 3 = x(-16) + 0 = 16x
4) m(2+1) - 6 + 1 = 3m - 5
5) m(10-8) = m(2) = 2m
6) x(1+1) - 5 - 4 = 2x - 9
7) x(4+5) = x(9) = 9x
8) x(7-1) + 3 + 5 = 6x + 8