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BlackZzzverrR [31]
3 years ago
8

What is the length of the dotted line in the diagram below? Leave your answer in

Mathematics
1 answer:
Andru [333]3 years ago
6 0

Answer:

30

Step-by-step explanation:

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How can congruent segments and lengths be created with a tool with no marked measurements?
QveST [7]
STEPS:
1. Using a straightedge, draw a reference line, if one is not provided.
2. Draw a dot on the reference line to mark your starting point for the construction.
3. Place the point of the compass on point A on the given figure.
4. Stretch the compass so that the pencil is exactly on B. Make a small arc through B.
(This small arc will show that you measured the length of the segment with your compass.)
5. Without changing the span of the compass, place the compass point on the starting point (dot) on the reference line and swing the pencil to create an arc crossing the reference line.
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4 0
3 years ago
Please help ! Math <br> -
harkovskaia [24]

Answer:

<u>f(x) = 2(x - 2)^2 - 1</u>

<u>vertex: (2, -1)</u>

Step-by-step explanation:

f(x) = 2x^2 - 8x + 7

<em>First, we find the vertex. </em>

x = -(-8)/4 = 2

y = 2(2)^2 - 8(2) + 7 = 2(4) - 16 + 7 = 8 - 9 = -1

vertex: (2, -1)

<em>Second, we write f(x) in vertex form. </em>

<em>we know that h and k have to be 2 and -1. </em>

2x^2 - 8x + 7 = a(x - 2)^2 - 1

<em>Since 8 - 1 = 7, we do this: </em>

f(x) = (2x^2 - 8x + 8) - 1

<em>Factor out the 2 and then factor the polynomial</em>

f(x) = 2(x^2 - 4x + 4) - 1

<em>factors of 4: </em>

1 4

2 2

-1 -4

<u>-2 -2 = -4</u>

<em>the function in vertex for is: </em>

f(x) = 2(x - 2)^2 - 1

8 0
3 years ago
A large university accepts 50​% of the students who apply. Of the students the university​ accepts, 35​% actually enroll. If 10,
lara31 [8.8K]

Answer:

3,500 students

Equation:

0.35 x 10,000 = 3,500

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gizmo_the_mogwai [7]

Option B.

(-5,-3) is located in Quadrant 3 only.

7 0
3 years ago
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a bird flies from the bottom of a canyon that is 62 2/5 feet below sea level to a nest that is 556 2/5 feet above sea level. wha
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im so sorry. U_U *tears fall*

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