X^2 = b^2-c^2
x^2= sqrt117^2-6^2
x^2=sqrt117×sqrt117-36
x^2=117-36
x^2=81
x=sqrt81
x=9cm
The height of the building to the nearest tenth of a meter is; 13 m
<h3>How to make use of Cosine Rule?</h3>
The slant line from the top of Trevor's head to the base of the building is gotten from Pythagoras theorem;
15/x = sin 36°
x = 15/sin 36
x = 25.52 m
Angle between that slant line and base of building is;
90 - tan⁻¹(1.5/14) = θ
θ = 83.88°
Remaining angle of the bigger triangle is;
180 - (36 + 83.88) = 60.12°
Thus, if the height of the building is h, then;
h/sin 36 = 25.52/sin 60.12
h = 13 m
Read more about Cosine Rule at; brainly.com/question/4372174
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The answer is 173 ft²
The area of the patio (A) is half of the area of the circle (A1) with a diameter of 21 ft:
A = A1/2
The area of the circle with radius r is:
A1 = π * r²
π = 3.14
We do not have the radius, but we know that it is a half of the diameter:
r = 21 ft / 2 = 10.5 ft
A1 = 3.14 * (10.5)² = 346.18 ft²
So, the area of the patio is:
A = A1/2
A = 346.18 ft² / 2
A = 173.09 ft² ≈ 173 ft²
The standard equation for the circle centre can be written by using this formula: (x-h)² + (y -k)² = r²
So, the equation in this case is: (x+6)² + (y-7)² = 81
Answer:
0.03125
Step-by-step explanation:
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