Set up a proportion.
2/3 = 12/x. Cross multiply the proportion.
2x = 36. Solve for x.
x = 18.
Answer:
A) 14
Step-by-step explanation:
BC is congruent to DC in saying this you can plug the equations to each other and solve for y and then put its back into the equation for BC to get the length.
3y+5=5y-1
subtract 3y from both sides --> 5=2y-1
add 1 to both sides --> 6=2y
now get y alone, divide by 2 by both side --> y=3
plug y in back to 5y-1 --> 5x3-1
15-1
BC = 14
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
• 1 + cot² x = csc²x and csc x = 
• sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Consider the left side
sin²Θ( 1 + cot²Θ )
= sin²Θ × csc²Θ
= sin²Θ × 1 / sin²Θ = 1 = right side ⇔ verified
-----------------------------------------------------------------
Consider the left side
cos²Θ - sin²Θ
= cos²Θ - (1 - cos²Θ)
= cos²Θ - 1 + cos²Θ
= 2cos²Θ - 1 = right side ⇒ verified
Answer:
3 hours
Step-by-step explanation:
speed of Bharat = 12kilometers / hour
speed of Ingrid=14 kilometers / hour
For this problem we'll be using formula relating time, distance and speed.i.e
Distance = speed x time
Suppose Bharat is riding at a distance of 'b' kilometers, therefore time taken by him will be:
Time = distance/ speed
Time= b/12 hours.
Also, Ingrid can ride the distance at this time with speed of 14km/hr
The distance would be,
Distance = speed x time
Distance = 14 x (b/12) => 14b/12
Distance= 7b/6
Let '
' be the distance that Bharat have covered after time 't'
therefore,
= 12 x t
Let '
' be the distance that Ingrid have covered after time 't'
therefore,
= 14 x t
In order to find the time when they are 78 kilometers apart, we will add
and
, because they are travelling in opposite direction creating distance between them.
So,
+
= 78
( 14 x t) + (12 x t) =78
14t + 12t =78
26t= 78
t= 78/26
t= 3hours.
thus, it will take 3 hours until they are 78 kilometers apart