Part 1) <span>Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?
step 1
find the slope m
m=(y2-y1)/(x2-x1)----></span>m=(25-7)/(30+24)----> m=18/54----> m=1/3
step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15
the answer Part 1) isy=(1/3)*x+15Part 2) <span>Is (51, 33) also on the same line?
</span>if the point (51.33) is on the line
y=(1/3)*x+15then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33
so
<span>the point does not belong to the given line
</span>
the answer Part 2) isthe point does not belong to the given line
see the attached figure
Answer (13 of the original arrangements are duplicates now, as
AAAF F F FDDDDCC, AAF F F FDDDDCCA, ..., CAAAF F F FDDDDC
are identical): 900900/13 = 69300.
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- First find the area of the whole circle
The equation is :
πr^2
Substitute the radius in:
π(5)^2
Solve:
Area of full circle = 25π
(Note : leave this answer in terms of 'pi' so it is easier to handle
Next, find the area of the sector
The equation for this is:
(angle/360) x πr^2
Substitute the values in:
(80/360) x π(5)^2
Solve :
Area of sector = (50/9)π
Now, find the area of the triangle:
1/2 absinC
Substitute the values in:
1/2(5)(5) x sin(80) = 12.31009691
Subtract this answer from the area of the sector
Answer = 5.14319607
Subtract this from the area of the whole circle
Answer = 73.39662073
To the nearest tenth, that would be 73.4 cm^2
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<h3>
Answer: Choice C, Ro, 270 </h3>
270 degree counterclockwise rotation around the origin
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Check out the diagram below. In the diagram, I only focus on points A and A'.
We have A = (-3,4) move to A ' = (4, 3). We see the x and y coordinates swap places. Then the new second coordinate -3 becomes positive, or it has flipped sign. So the rule applied here is
which describes a 90 degree clockwise rotation; which is equivalent to a 270 degree counterclockwise rotation
The other points follow the same idea.