Answer:
The correct option is;
Decrease b.
Step-by-step explanation:
The given information are;
The function in the question is given by the equation, y = a·cos(b·x)
Where;
a > 0 and b > 0
The location of the x-intercept is given by the values of x when y = 0 which are obtained as follows;
When y = 0, y = a·cos(b·x) = 0
Therefore;
cos(b·x) = 0/a = 0
∴ b·x = cos⁻¹(0) = π/2, 3·π/2, (4·n×π + π)/2
Therefore, as b decreases, x increases.
<span>Starting with x−24/x<10 multiply everything by x.
x^2-24<10x
Subtract 10x from both sides.
x^2-10x-24 < 0
Factor.
(x-12)(x+2) < 0
(x+2) is always positive since x > 0, but (x-12) is negative when x is a value between 0 and 12. This negative value for (x-12) satisfies that the left side is less than 0. Thus the solution set for x is (0,12).</span>
(x + 2)(x + 2)(x + 2)
(x^2 + 4x + 4)(x + 2)
x^3 + 4x^2 + 4x + 2x^2 + 8x + 8
Simplify
Solution: x^3 + 6x^2 + 12x + 8
The answer is A
x^2+3x-18 in factored form leaves us the two factors of;
(x+6)(x-3)
So from your choices (x-3) is the answer
