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Black_prince [1.1K]
3 years ago
7

I need the variables in the chart to be answered.

Chemistry
1 answer:
NeTakaya3 years ago
8 0

Answer:

Explanation:

Given data:

Initial temperature = 295 K

Initial volume = 1.0 L

Values of A,B, C and D.

Solution:

As it is mentioned in question V₁ and T₁ are the first readings of table thus,

V₁/T₁  =  V₂/T₂

V₁ = Initial volume

T₁  = Initial temperature

V₂ = Final volume

T₂ = Final temperature

For A:

V₁/T₁  =  V₂/T₂

1.0 L / 295 K = 1.3 L /T₂

T₂ = 1.3 L × 295 K / 1.0 L

T₂ = 383.5 K

For B:

V₁/T₁  =  V₂/T₂

1.0 L / 295 K = V₂ /250 k

V₂ =  1.0 L × 250 k/ 295 K

V₂ = 250 k.L/ 295 K

V₂ = 0.85 L

For C:

V₁/T₁  =  V₂/T₂

1.0 L / 295 K = V₂ /325 k

V₂ =  1.0 L × 325 k/ 295 K

V₂ = 325 k.L/ 295 K

V₂ = 1.1 L

For D:

V₁/T₁  =  V₂/T₂

1.0 L / 295 K = 0.75 L /T₂

T₂ = 0.75 L × 295 K / 1.0 L

T₂ = 221.25 K

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elena-14-01-66 [18.8K]

Answer:

A. 15859.2 L or 15900 L

B. 0.629 mol

Explanation:

At STP, one mole is equal to approximately 22.4 L

L or mL is volume, so you are attempting to solve for L or mL.

A.

708 mol x (22.4 L/1 mol) = 15859.2 L (w/ significant figures included - 15900 L)

B.

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5 0
3 years ago
Compounds A and B are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 g of sulf
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Answer:

1.5

Explanation:

Given that :

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Compound B:

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Comparing the ratios :

Compound A:

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S/0 = 6.0g S / 5.99g O

Compound B :

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S / O = 8.60g S / 12.88g O

Mass Ratio of A / mass Ratio of B

(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)

(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)

(6 × 12.88) / (5.99 × 8.60)

= 77.28 / 51.514

= 1.50017

= 1.5

4 0
4 years ago
No clue what do to do so help please lol
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I don’t know what the answer is just need points sorry
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Explanation:

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4 years ago
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