To find out how many hours it rained, divide the total rise in the river by the amount it rose every hour.

First convert the mixed number into an improper fraction. We do this by multiplying the denominator to the whole number, adding it to the numerator, which becomes our new numerator, and we keep the denominator the same:

When dividing fractions we flip(the reciprocal) the one we're dividing by and multiply:

Multiply the numerators and denominators together:

Simplify by dividing:

So it rained for 10 hours.
Answer:
the answer is 12.24 .
Step-by-step explanation:
that answer is right is because when you add of those you get 530 , then you divide by how many numbers there are which is 7 , which equals to 75.7 . when you get that number ( 75.7) you subtract that number to 65,90,85,70,70,95, and 55 . when you get the total of all of those you add those . which is 10.7, 14.3 , 9.3 , 5.7 , 5.7 , 19.3 , and 20.7 . from adding those you get 85.7. you divide by 7 and get 12.24 . hope this helps :) .
The answer is 22.8
Cos 64 = adj./hypotenuse
Cos64=10/x
X(cos64)=10
X= 10/cos64
= 22.8
<span>ow far does the first car go in the 2 hours head start it gets?
Now, at t = 2 hours, both cars are moving. How much faster is the second car than the first car? How long will it take to recover the head start? You can determine this by dividing the head start by the difference in the two speeds. If car 1 has a 20 mile head start, and car 2 is 5 mph faster, then it will take 20/5 = 4 hours to catch up.
</span>You could also write two equations, one for each car, showing how far they have gone in a variable amount of time. Set the two equations equal to each other and solve for the value of the time. Note that the second car's equation will use (t-2) for the time, because it doesn't start driving until t = 2.