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IceJOKER [234]
3 years ago
6

Find three consecutive odd integers whose sum is 117

Mathematics
2 answers:
irina [24]3 years ago
8 0
37, 39, 41 is the answer
Delvig [45]3 years ago
6 0

First odd integer: 2k+1 (note: using 2k+1 insures it is an odd integer)

Second odd integer: 2k+3

Third odd integer: 2k+5

First + Second + Third = 117

2k+1 + 2k+3 + 2k+5 = 117 <em>substituted for First, Second, and Third</em>

6k + 9 = 117 <em>added like terms</em>

6k = 108 <em> subtracted 7 from both sides</em>

k = 18

First: 2k + 1 = 2(18) + 1 = 36 + 1 = 37

Second: 2k + 3 = 2(18) + 3 = 36 + 3 = 39

Third: 2k + 5 = 2(18) + 5 = 36 + 5 = 41

Answer: 37, 39, 41

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<h3>What is an Equation ?</h3>

An equation is a mathematical statement which equates two algebraic expression with an equal sign.

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The total no. of legs of a goats sold will be 4g

and the total number of legs of a hens sold will be 2h

and it is given that

4g +2h = 32

The system of equation formed is

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Multiplying equation (1) by 2 and then (1) - (2)

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Therefore the number of goats sold is 4 and hens sold is 8.

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