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Leya [2.2K]
3 years ago
11

Please answer this question with any of the 4 choices i have been struggling with this

Mathematics
2 answers:
kotegsom [21]3 years ago
7 0

Answer:

Choice A. \frac{2}{3}

Step-by-step explanation:

Turn the mixed numbers into improper fractions:

  • \frac{14}{9} /\frac{7}{3}

Flip the second term and multiply:

  • \frac{14}{9} /\frac{3}{7}
  • \frac{42}{63}

Simplify:

  • \frac{2}{3}
tiny-mole [99]3 years ago
7 0

Answer:

A

Step-by-step explanation:

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Two groups of tourists are on the same floor of a skyscraper they are visiting, and they board adjacent elevators at the same ti
Mariulka [41]

Let time be x distance be y

  • 140x=y-(1)
  • 290x=360-y-(2)

Put value in eq(2)

\\ \rm\longmapsto 290x=360-(140y)

\\ \rm\longmapsto 440x=360

\\ \rm\longmapsto x=1.2min

Put it in eq(1)

  • d=1.2(140)=168m
7 0
2 years ago
Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?
erik [133]

Let

A-----> \frac{7}{8}

B-----> \frac{11}{10}

C-----> 1

we know that

Point A-------> Multiply numerator and denominator by 10

\frac{7*10}{8*10} =\frac{70}{80}

Point B-------> Multiply numerator and denominator by 8

\frac{11*8}{10*8} =\frac{88}{80}

Point C-------> Multiply numerator and denominator by 80

\frac{1*80}{1*80} =\frac{80}{80}

Find the distance Point A to Point C

\frac{80}{80} -\frac{70}{80} =\frac{10}{80}

Find the distance Point B to Point C

\frac{88}{80} -\frac{80}{80} =\frac{8}{80}

therefore

\frac{8}{80} < \frac{10}{80}

Point B is closer to Point C

\frac{11}{10} is closer to 1

the answer is

\frac{11}{10} is closer to 1

5 0
3 years ago
Read 2 more answers
If each foot of water in a lake screens out 60% of the light above, what percent of the light passes through 5 feet of water?
BartSMP [9]
The amount of light passing through each foot the water in the lake = 100% - 60% = 40%
The percent of light passing through 5 feet of water = 0.4^5 = 0.01024 = 1.02%
8 0
3 years ago
SOMEONE PLEASE HELP!!! ​HURRY
MAXImum [283]

Answer:

Slope of the line DV = -1

Step-by-step explanation:

Let point D (-5, 1) be (x_{1}, y_{1})

Let point V (-1, -3) be (x_{2}, y_{2})

m=\frac{y_2-y_1}{x_2-x_1}

Plug in the appropriate values,

m = \frac{-3-1}{-1-(-5)} = \frac{-4}{4} = -1

slope equals -1

4 0
2 years ago
Find an equation of the tangent line to the hyperbola: x^2/a^2 - y^2/b^2 = 1 at the point (x0,x1)
musickatia [10]

The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
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hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1

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8 0
3 years ago
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