Let time be x distance be y
Put value in eq(2)



Put it in eq(1)
Let
A-----> 
B-----> 
C-----> 
we know that
Point A-------> Multiply numerator and denominator by 

Point B-------> Multiply numerator and denominator by 

Point C-------> Multiply numerator and denominator by 

Find the distance Point A to Point C

Find the distance Point B to Point C

therefore

Point B is closer to Point C
is closer to 
the answer is
is closer to 
The amount of light passing through each foot the water in the lake = 100% - 60% = 40%
The percent of light passing through 5 feet of water = 0.4^5 = 0.01024 = 1.02%
Answer:
Slope of the line DV = -1
Step-by-step explanation:
Let point D (-5, 1) be 
Let point V (-1, -3) be 

Plug in the appropriate values,

slope equals -1
The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1
</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)