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kkurt [141]
3 years ago
5

Find the measure of the complement of a 18 degree angle

Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0

90-18=72

complement = 72

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3.4x-7.2=5.8x+24 <br> I need help
notka56 [123]
3.4x - 7.2 = 5.8x + 24
3.4 - 5.8x = 24 + 7.2
-2.4x = 31.2
-2.4x / -2.4 = 31.2 / -2.4
x = -13
4 0
3 years ago
What is the area in square centimeters of the trapezoid below​
Dovator [93]

Answer:

39.6 cm²

Step-by-step explanation:

The formula for the area of a trapezoid is given as:

Area of a Trapezoid = 1/2(a + b) h

Where, from the question:

a = 8.9 cm

b = 5.5 cm

h = 5.5cm

Hence,

1/2 (8.9cm + 5.5cm) × 5.5cm

= 1/2 × 14.4 cm × 5.5 cm

= 39.6 cm²

Area of the Trapezoid = 39.6 cm²

5 0
3 years ago
What is the approximate value of X round to the nearest 10th
Alik [6]

Answer:

The correct answer is C) 4.6

Step-by-step explanation:

To find this, use the trigonometry functions. In this case, since we have the hypotenuse and are looking for the opposite, we use Sin.

Sin(α) = OPP/HYP

Sin(50) = x/6

6Sin(50) = x

4.6 = x

6 0
3 years ago
What are the intercepts of the equation 4x-6y-5z=60
Annette [7]
To find the intercept of a variable in a equation with more than one variable, you need to equal the others variables to zero.

-> 4x -6y -5z = 60

-> X-Intercept:
To find the X intercept, equal the Y and Z values to 0.
(Y = 0; Z = 0)

4x -6(0) -5(0) = 60
4x = 60
x = 60/4
x = 15

-> Y-Intercept:
To the Y intercept it's the same thing, equal the another variable values to 0.
(X = 0; Z = 0)

4(0) -6y -5(0) = 60
-6y = 60
-y = 60/6
-y = 10        x(-1)
y = -10

-> Z-Intercept:
(X = 0; Y = 0)

4(0) -6(0) -5z = 60
-5z =60
-z = 60/5
-z = 12         x(-1)
z = -12

Answer: The intercepts for this equation (15,-10,-12).
Or: x = 15, y = -10, z = -12.
6 0
4 years ago
You are designing an open-top cylindrical container. The cylinder must have a volume of 81π cm3 . The bottom of the container mu
stira [4]

Answer:

Minimum dimensions are r=3cm, h=9cm

Minimum Cost=$254.47

Step-by-step explanation:

Volume of a Cylinder=πr²h

Volume of the Open Top Cylinder=81π cm³.

Therefore:

πr²h=81π

The bottom costs $3 per cm² and the side costs $1 per cm².

Total Surface Area of the open top Cylinder= πr²+2πrh

Cost, C=3πr²+2πrh

As the Volume is fixed.

πr²h=81π

r²h=81

h=81/r²

Modifying C,

C=3\pi r^{2}+2 \pi r \frac{81}{r^{2}}

C=3\pi r^{2}+ \frac{162 \pi}{r}

We differentiate C with respect to r

C'=6\pi r -\frac{162 \pi}{r^2}

At the minimum cost, C'=0.

Next we solve C'=0 for r

6\pi r -\frac{162 \pi}{r^2}=0

6πr³-162π=0

6πr³=162π

r³=27

r=3

The dimensions of the cylinder at minimum cost are therefore:

r=3 cm

h=81/9=9cm

The minimum cost of the Cylinder

C=3πr²+2πrh

=(3XπX3²)+(2XπX3X9)

=$254.47

8 0
4 years ago
Read 2 more answers
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