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Darya [45]
3 years ago
7

If a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.

Mathematics
1 answer:
Ierofanga [76]3 years ago
5 0
According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in   all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3. 
</span>hence proved


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