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Inessa05 [86]
3 years ago
10

Can someone tell me what I should know how to do in geometry?

Mathematics
1 answer:
Alexus [3.1K]3 years ago
6 0
You should know how to ............
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HELP PLS! WILL REWARD BRAINLIEST, TYSM !
Helga [31]

Answer:

b and d

Step-by-step explanation:

they both have b

5 0
3 years ago
Read 2 more answers
Which of the following equations is the accurate representation of the following​ statement?
k0ka [10]

Answer:

5x - \frac{x}{3} = \frac{1}{4}

Step-by-step explanation:

6 0
3 years ago
Please help I forgot how to do this
timofeeve [1]

Answer:

See answer below.

Step-by-step explanation:

2≥  g/-4

2( -4)  ≥  g

-8 ≥ g

graph :   Closed circle at -8 and shade to the left of -8  

                                         

3 0
2 years ago
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
Kryger [21]

For this case we have the following functions:

f (x) = 4 - x ^ 2\\g (x) = 6x

The first thing we must do for this case is to subtract both functions.

We have then:

(g - f) (x) = g (x) - f (x)

Substituting we have:

(g - f) (x) = (6x) - (4 - x ^ 2)

Rewriting we have:

(g - f) (x) = x ^ 2 + 6x - 4

Evaluating the obtained function for x = 3 we have:

(g - f) (3) = (3) ^ 2 + 6 (3) - 4\\(g - f) (3) = 23

Answer:

The value of the function evaluated at x = 3 is:

(g - f) (3) = 23

7 0
3 years ago
Read 2 more answers
Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.
ratelena [41]

Both functions are the solution to the given Laplace solution.

Given Laplace's equation: u_{x x}+u_{y y}=0

  • We must determine whether a given function is the solution to a given Laplace equation.
  • If a function is a solution to a given Laplace's equation, it satisfies the solution.

(1) u=e^{-x} \cos y-e^{-y} \cos x

Differentiate with respect to x as follows:

u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x

Differentiate with respect to y as follows:

u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x

Supplement the values in the given Laplace equation.

e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0

The given function in this case is the solution to the given Laplace equation.

(2) u=\sin x \cosh y+\cos x \sinh y

Differentiate with respect to x as follows:

u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y

Differentiate with respect to y as follows:

u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y

Substitute the values to obtain:

-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0
The given function in this case is the solution to the given Laplace equation.

Therefore, both functions are the solution to the given Laplace solution.

Know more about Laplace's equation here:

brainly.com/question/14040033

#SPJ4

The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)

6 0
2 years ago
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