Question

This Question: 1 pt

Answer 1

Answer with Step-by-step explanation:

We are given that

Height of ball after t seconds is given by

$s(t)=-4t^2+20t+2$

a.Substitute the value of t=1

$s(1)=-4(1)+20(1)+2=-4+20+2=18 ft$

b.Differentiate w.r.t x

$s'(t)=-8t+20$

$s'(t)=0$

$-8t+20=0$

$8t=20$

$t=\frac{20}{8}=2.5$

Again differentiate w.r.t t

$s''(t)=-8$

Hence, the height is maximum at t=2.5 s

$s(2.5)=-4(2.5)^2+20(2.5)+2=27$

Maximum height of the baseball=27 ft